uniform function call syntax
This commit is contained in:
@@ -6,21 +6,21 @@ func main[] : i64
|
||||
sum := 0
|
||||
|
||||
for i in 1..10
|
||||
sum += array.nth(s1, i)
|
||||
sum += s1->nth(i)
|
||||
for i in 0..10
|
||||
sum += array.nth(s2, i)
|
||||
sum += s2->nth(i)
|
||||
for i in 20..100
|
||||
sum += array.nth(s3, i / 10) + array.nth(s1, i % 10)
|
||||
sum += s3->nth(i / 10) + s1->nth(i % 10)
|
||||
|
||||
for i in 1..10
|
||||
sum += array.nth(s1, i) + 7
|
||||
sum += s1->nth(i) + 7
|
||||
for j in 1..10
|
||||
sum += array.nth(s1, i) + 7 + 3 + array.nth(s1, j)
|
||||
sum += s1->nth(i) + 7 + 3 + s1->nth(j)
|
||||
for j in 0..10
|
||||
sum += array.nth(s1, i) + 7 + 3 + array.nth(s2, j)
|
||||
sum += s1->nth(i) + 7 + 3 + s2->nth(j)
|
||||
for j in 20..100
|
||||
sum += array.nth(s1, i) + 7 + 3 + array.nth(s3, j / 10) + array.nth(s1, j % 10)
|
||||
sum += s1->nth(i) + 7 + 3 + s3->nth(j / 10) + s1->nth(j % 10)
|
||||
|
||||
sum += array.nth(s1, 1) + 8
|
||||
sum += s1->nth(1) + 8
|
||||
|
||||
io.println_i64(sum)
|
||||
|
||||
Reference in New Issue
Block a user